0
已解决
30分,对了1,6,8测试点
#include<iostream>
#include<cstdio>
using namespace std;
double a,sum;
int main(){
cin>>a;
if(a<=100000){
printf("%.2f",a*0.1);
}
else if(a>100000&&a<200000){
sum=10000+(a-100000)*0.075;
printf("%.2f",sum*1.0);
}
else if(a>=200000&&a<400000){
sum=200000*0.075+(a-200000)*0.05;
printf("%.2f",sum*1.0);
}
else if(a>=400000&&a<600000){
sum=400000*0.05+(a-400000)*0.03;
printf("%.2f",sum*1.0);
}
else{
sum=600000*0.03+(a-600000)*0.15;
printf("%.2f",sum*1.0);
}
return 0;
}