0
已采纳
int a,b,n;
cin>>a>>b>>n;
cout<<(a/n)+(b/n)<<" "<<(a%n)+(b%n)<<"\n";
cout<<(a+b)/n<<" "<<(a+b)%n<<"\n";
0
0
0
0
int a,b,n;
cin>>a>>b>>n;
cout<<(a/n)+(b/n)<<" "<<(a%n)+(b%n)<<"\n";
cout<<(a+b)/n<<" "<<(a+b)%n<<"\n";