问题标题: 有dalao有打地鼠的C++代码吗

@臧启亚 程序不太对

1

#include<stdio.h>  
#include<stdlib.h>  
#include<time.h>  
int main(){  
    int times = 0;  
    int mousey = 0, mousex= 0;  
    int num = 0;  
    srand(time(0));  
    int posy = 0,posx = 0;  
    int hits = 0,missed = 0;  
    int row = 0,col = 0;  
    //获取游戏次数  
    printf("请输入游戏次数：");  
    scanf("%d",&mousex);  
    //打印地图  
    printf("* * *\n* * *\n* * *\n");  
    //游戏过程  
    for(num = 1;num <= times;num++){  
        //获得老鼠和锤子的位置  
        mousey = rand() % 3 + 1;  
        mousex = rand() % 3 + 1;  
        do{  
            printf("请输入锤子的位置：");  
            scanf("%d %d",&posy,&posx);  
        }while(posy < 1 || posy > 3 || posx < 1 || posx > 3);  
    //修改打中和错过的个数  
    if(mousey == posy && mousex == posx){  
        hits++;  
    }else{  
        missed++;  
    }  
    //打印地图  
        for(row = 1;row <= 3;row++){  
            for(col = 1;col <= 3;col++){  
                if(row == posy && col == posx){  
                    printf("O ");  
                }  
                else if(row == mousey && col == mousex){  
                    printf("X ");  
                }  
                else{  
                    printf("* ");  
                }  
            }  
            printf("\n");  
        }  
        //提示是否打中  
        if(mousey == posy && mousex == posx){  
            printf("恭喜你，打中了！\n");  
        }  
        else{  
            printf("很遗憾，没有打中\n");  
        }  
        //打印总成绩  
        printf("打中%d次，错过%d次\n",hits,missed);  
    }  
    return 0;  
}  

编译如下：

https://www.cnblogs.com/homes/p/5095058.html