1
已解决
初级启示者
运行代码，等待开始，10秒后按下任意键，比谁的误差更小~~~
这回没法作弊了吧~~~
#include <stdio.h>
#include <time.h>
#include <windows.h>
#include <conio.h>
asm(".TXT:\n"
" .ascii \"\\312\\261\\274\\344\\243\\272%04dms \\316\\363\\262\\356\\243\\272%04dms\\n\\0\"\n"
".YZM:\n"
" .ascii \"\\321\\351\\326\\244\\264\\372\\302\\353\\243\\272%X%X\\0\"\n"
);
int main() {
for (int i = 3; i >= 1; i--) {
printf("将在%d秒后开始计时\n", i);
Sleep(1000);
}
printf("开始！\n\n");
clock_t a = clock();
getch();
clock_t b = clock() - a;
printf("您的成绩：\n");
asm(
"movl $10000, %eax\n"
" subl -12(%rbp), %eax\n"
" testl %eax, %eax\n"
" jle .AA\n"
" movl $10000, %eax\n"
" subl -12(%rbp), %eax\n"
" jmp .BB\n"
".AA:\n"
" movl -12(%rbp), %eax\n"
" subl $10000, %eax\n"
".BB:\n"
" movl -12(%rbp), %edx\n"
" movl %eax, %r8d\n"
" leaq .TXT(%rip), %rcx\n"
" call printf\n"
" movl -12(%rbp), %eax\n"
" andl $58954, %eax\n"
" orl $289, %eax\n"
" movl %eax, %edx\n"
" movl -12(%rbp), %eax\n"
" andl $44849, %eax\n"
" xorl $675, %eax\n"
" orl $44, %eax\n"
" movl %edx, %r8d\n"
" movl %eax, %edx\n"
" leaq .YZM(%rip), %rcx\n"
" call printf\n"
);
return 0;
}要是编译不了，下EXE版：https://github.com/xgugugu/cdtpoints/releases/download/1/time.exe
第一给100豆（需要截屏）
薛乘志在2022-07-25 16:12:11追加了内容
改标题
最好成绩算吗？
