0
已解决
1617 检查作业(check)
25分代码:
果断超时(就最多16毫秒):
#include<iostream>
#include<string>
#include<cstring>
using namespace std;
int main()
{
long long n,wrong=0;
cin>>n;
int jia1[10010],jia2[10010],he[10010];
char jiahao[10010],denghao[10010];
for(int i=1;i<=n*n;i++)
{
cin>>jia1[i]>>jiahao[i]>>jia2[i]>>denghao[i]>>he[i];
if(jia1[i]+jia2[i]!=he[i])
wrong++;
}
cout<<wrong;
return 0;
}
求大神指导!!!