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已解决
HELP PLEH ! ! !
谁能帮帮我这个宇宙大蒟蒻啊 ? ? ?
#include<iostream>
using namespace std;
int main()
{
int a,b,c;
cin>>a>>b>>c;
if(a>b&&a>c)
{
if(b>c)
cout<<c<<" "<<b<<" "<<a;
}
if(b>a&&b>c)
{
if(a>c)
cout<<c<<" "<<a<<" "<<b;
}
if(c>b&&c>a)
if(a>b)
cout<<b<<" "<<a<<" "<<c;
if(a>b&&a>c)
{
if(b<c)
cout<<b<<" "<<c<<" "<<a;
}
if(b>a&&b>c)
{
if(a<c)
cout<<a<<" "<<c<<" "<<b;
}
if(c>b&&c<a)
{
if(b>a)
cout<<a<<" "<<b<<" "<<c;
}
return 0;
}
这是90分代码,
请各位大佬帮我看看!!!
感激不尽!!!
1
已采纳
很简单,可以用min和max
int zx=min(min(a,b),c);
int zd=max(max(a,b),c);
cout<<zx<<" "<<((a+b+c)-zd-zx)<<" "<<zd<<endl;
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