0
已解决
新手光能
#include<iostream>
using namespace std;
int main(){
double a,b,x,c,d;
cin>>a>>b>>c;
x=a+b+c;
d=x-(int)x;
if(d>=0.1&&d<=0.5){
cout<<(int)x<<".0";
}
else if(d>=0.5&&d<=0.9){
cout<<(int)x<<".5";
}
else cout<<x;
return 0;
}
0
已采纳
资深守护
double a,b,c,d,n,k;
输入a,b,c;
d=(a+b+c)*10;
k=d;
d=(int)d%10;
如果(d>=0与d<=4) printf("%.1f",(int)k/10+0.0);
否则 如果(d>=5与d<=9) printf("%.1f",(int)k/10+0.5);
别忘了文件头
#include <iostream>
#include <cstdio>
0
资深守护
望采纳，谢谢！！！
