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已采纳
int a,b;
cin>>a>>b;
if((a%2==0&&a<=9&&a>=0)&&(b%2==0&&b<=6))
cout<<"Yes"<<endl;
if((a%2==1&&a<=9&&a>=0)&&(b%2==1&&b<=6))
cout<<"Yes"<<endl;
if(b==7)
cout<<"Yes"<<endl;
if((a%2==0)&&(b%2!=0&&b<=6))
cout<<"No"<<endl;
if((a%2==1)&&(b%2!=1&&b<=6))
cout<<"No"<<endl;
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if判断 if(b%2==1&&b!=7)//如果今天的星期数是奇数且不是7 { if(a%2==0) cout<<"No"; else cout<<"Yes"; } else if(b%2==0)//如果今天的星期数是偶数 { if(a%2==1) cout<<"No"; else cout<<"Yes"; } else { cout<<"Yes"; }
可供参考。
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