问题标题: 酷町堂：1111

用循环，或者用直接输出（暴力）

#include<iostream>
using namespace std;
int main(){
    cout<<"*"<<endl<<"**"<<endl<<"***"<<endl<<"****"<<endl<<"*****"<<endl<<"******"<<endl<<"*******"<<endl;
    return 0;
}

望采纳🙏

直接输出

直接输出，或双重循环

暴力输出

    cout<<"*"<<endl; 
    cout<<"**"<<endl;
    cout<<"***"<<endl;
    cout<<"****"<<endl;
    cout<<"*****"<<endl;
    cout<<"******"<<endl;
    cout<<"*******";

AC愉快

char a='*';
    cout<<a<<endl<<a<<a<<endl<<a<<a<<a<<endl<<a<<a<<a<<a<<endl<<a<<a<<a<<a<<a<<endl<<a<<a<<a<<a<<a<<a<<endl<<a<<a<<a<<a<<a<<a<<a;

直接输出*

直接输出就行了。

比如：

    cout<<"*"<<endl; 
    cout<<"**"<<endl;
    cout<<"***"<<endl;
    cout<<"****"<<endl;
    cout<<"*****"<<endl;
    cout<<"******"<<endl;
    cout<<"*******";

解宇乐在2019-12-05 19:56:53追加了内容

还有一种方法，循环。

    for(1~7)
    {
        for(1~a)       
            cout<<"*";
        cout<<endl;
        a++
    }

还要定义a哟

cout<<"*"<<endl; 
    cout<<"**"<<endl;
    cout<<"***"<<endl;
    cout<<"****"<<endl;
    cout<<"*****"<<endl;
    cout<<"******"<<endl;
    cout<<"*******";

 cout<<"*"<<endl;
    cout<<"**"<<endl;
    cout<<"***"<<endl;
    cout<<"****"<<endl;
    cout<<"*****"<<endl;
    cout<<"******"<<endl;
    cout<<"*******"<<endl;

    cout<<"*"<<endl;
    cout<<"**"<<endl;
    cout<<"***"<<endl;
    cout<<"****"<<endl;
    cout<<"*****"<<endl;
    cout<<"******"<<endl;
    cout<<"*******"<<endl;

简单

循环and直接输出

cout<<"*"<<endl;

cout<<"**"<<endl;

cout<<"***"<<endl;

cout<<"****"<<endl;

cout<<"*****"<<endl;

cout<<"******"<<endl;

cout<<"*******";

拜托了

直接输出

直接输出，保证100

 cout<<"*"<<endl;
    cout<<"**"<<endl;
    cout<<"***"<<endl;
    cout<<"****"<<endl;
    cout<<"*****"<<endl;
    cout<<"******"<<endl;
    cout<<"*******"<<endl;

cout<<"*"<<endl;

cout<<"**"<<endl;

cout<<"***"<<endl;

cout<<"****"<<endl;

cout<<"*****"<<endl;

cout<<"******"<<endl;

cout<<"*******";

return 0;

#include<iostream>
#include<cstdio>
using namespace std;
string k, d;
int n;
int a[1000001], b[1000001];
int a1, a2;
bool win(int n, int m) {
    if (n == 1 && m == 2 || n == 2 && m == 3 || n == 3 && m == 1) return true;
    return false;
}
int main() {
    cin >> k >> d;
    cin >> n;
    for (int i = 0; i < k.size(); i++) {
        if (k[i] == 'A') k[i] = '1';
        else if (k[i] == 'B') k[i] = '2';
        else if (k[i] == 'C') k[i] = '3';
    }
    for (int i = 0; i < d.size(); i++) {
        if (d[i] == 'A') d[i] = '1';
        else if (d[i] == 'B') d[i] = '2';
        else if (d[i] == 'C') d[i] = '3';
    }
    for (int i = 0; i < k.size(); i++) {
        a[i] = k[i] - 48;
    }
    for (int i = 0; i < d.size(); i++) {
        b[i] = d[i] - 48;
    }
    for (int i = 0; i < n; i++) {
        int x = a[i % k.size()], y = b[i % d.size()];
        if (win(x, y)) a1++;
        else if (win(y, x)) a2++;
    }
    if (a1 > a2) cout << "酷酷赢"<<' '<<a1;
    else if (a1 < a2) cout << "丁丁赢" << ' ' << a2;
    else  cout << "平局";
    return 0;
}

张岳恒在2020-08-26 12:20:49追加了内容

不好意思，发错了

枚举！！

hhhhhhhhhhh

暴力输出没问题

#include<iostream>
using namespace std;
int main(){
    cout<<"*"<<endl<<"**"<<endl<<"***"<<endl<<"****"<<endl<<"*****"<<endl<<"******"<<endl<<"*******"<<endl;
    return 0;
}

望采纳

可以直接输出的哦！！！

 cout<<"*"<<endl;
    cout<<"**"<<endl;
    cout<<"***"<<endl;
    cout<<"****"<<endl;
    cout<<"*****"<<endl;
    cout<<"******"<<endl;
    cout<<"*******";
    return 0;