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已采纳
if(a<b)cout<<0<<" "<<a+b<<endl;
if(a>b)cout<<a+b<<" "<<0<<endl;
if(a==b)cout<<a<<" "<<b<<endl;
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if(a<b)cout<<0<<" "<<a+b<<endl;
if(a>b)cout<<a+b<<" "<<0<<endl;
if(a==b)cout<<a<<" "<<b<<endl;
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核心代码:
if(a<b)cout<<0<<" "<<a+b<<endl;
else if(a>b)cout<<a+b<<" "<<0<<endl;
else if(a==b)cout<<a<<" "<<b<<endl;
就是哪个数大就加上另一个数,较小的数就清空为0;如果一样大就不变。记得中间用空格分隔
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if(b>=h) { if(b>h) cout<<b+h<<" "<<0<<endl; else cout<<b<<" "<<h<<endl; } else cout<<0<<" "<<b+h<<endl;
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思路全对,但只用输入、输出一次,因为它是样例,题目会给你多个样例。(c,d是干嘛的)
刘凯南在2018-01-26 21:18:23追加了内容
e,f赋值时e在前面赋值,f在后面赋值才对
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int a,b;
cin>>a>>b;
if(a>b)
cout<<a+b<<" "<<"0";
if(a==b)
cout<<a<<" "<<b;
if(a<b)
cout<<"0"<<" "<<b+a;
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我是这样写的:
核心代码:
int a,b;
cin>>a>>b;
if(a>b)
cout<<a+b<<" "<<"0";
if(a==b)
cout<<a<<" "<<b;
if(a<b)
cout<<"0"<<" "<<b+a;
求采纳!
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