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已采纳
for(int i=1;i<=n;i++){
for(int k=0;k<n-i;k++)
cout<<" ";
for(int j=1;j<=2*i-1;j++)
cout<<j;
cout<<endl;
}
for(int i=1;i<=n-1;i++){
for(int k=1;k<=i;k++)
cout<<" ";
for(int j=1;j<=2*(n-i-1)+1;j++)
cout<<j;
cout<<endl;
}
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